Question

the sensor in the torso of a crash-test dummy records the magnitude and direction of the net force acting on the dummy. if the dummy is thrown forward with a force of 130.0 N while simultaneously being hit from the side with a force of 4500.0 N, what force will the sensor report?

Answer 1

The sensor in the crash-test dummy will record a net force of approximately 4501.9 N, calculated using the Pythagorean theorem to combine the perpendicular forces acting on the dummy.

Step-by-step explanation:

The problem described involves calculating the net force acting on a crash-test dummy, taking into account two perpendicular forces.

We can use the Pythagorean theorem to find the magnitude of the net force since the forces act at right angles to each other.

The formula for the magnitude of the net force (Fnet) is Fnet = √(Fx^2 + Fy^2), where Fx is the force in the forward direction and Fy is the force from the side.

We are given a forward force (Fx) of 130.0 N, and a side force (Fy) of 4500.0 N.

Plugging these values into the formula, we get Fnet = √(130.0 N)^2 + (4500.0 N)^2

= √(16900 + 20250000) N^2

= √20266900 N^2

≈ 4501.9 N.

Therefore, the sensor will report a net force of approximately 4501.9 N acting on the crash-test dummy.