68.8k views
4 votes
If the probability of a swan drowning is 0.23 and the probability of a swan swimming is 0.57, find the probability of a swan who can swim AND does not drown. Assume the event are independent.

User Josemota
by
8.3k points

1 Answer

7 votes
Sure! To find the probability of a swan who can swim AND does not drown, we can multiply the probabilities of these two independent events.

The probability of a swan swimming is 0.57, and the probability of a swan not drowning is the complement of the probability of drowning, which is 1 - 0.23 = 0.77.

So, the probability of a swan who can swim AND does not drown is 0.57 * 0.77 = 0.4399, or approximately 0.44.
User Yuyang He
by
8.1k points