Question

A quarterback throws a pass to a receiver, who catches it at the same height as the pass is thrown. The ball is thrown with an initial velocity of 15 [m/s] along the x- direction, at the angle of 250 above the horizontal. What is the horizontal component of the ball's velocity when the receiver catches it?

Answer 1

The horizontal component of the ball's velocity when the receiver catches it is approximately 13.605 m/s.

Step-by-step explanation:

To find the horizontal component of the ball's velocity, we can use the formula:

horizontal velocity = initial velocity * cos(angle)

Plugging in the given values, we have:

initial velocity = 15 m/s

angle = 25°

Using a calculator to find the cosine of 25°, we get:

cos(25°) ≈ 0.907

Multiplying the initial velocity by the cosine of the angle, we find:

horizontal velocity = 15 m/s * 0.907 ≈ 13.605 m/s

Therefore, the horizontal component of the ball's velocity when the receiver catches it is approximately 13.605 m/s.