233k views
0 votes
Simplify and find each value. 13.75(1(1)/(2))-7(1)/(4)(1(1)/(2))

User Mcherm
by
8.5k points

2 Answers

7 votes

Final answer:

To simplify and find the value of the expression, multiply the whole numbers and fractions separately, and then subtract the second term.

Step-by-step explanation:

To simplify and find the value of the expression, we can follow these steps:

1. Multiply the whole numbers together: 13.75 * 1 = 13.75.

2. Multiply the fractions together: (1/2) * (1/2) = 1/4.

3. Subtract the second term: 13.75 - 7 * (1/4) = 13.75 - 1.75 = 12.

The student is asking how to simplify and find the value of the expression 13.75(1\(1)/(2))-7(1)/(4)(1\(1)/(2)). First, we need to convert the mixed numbers to improper fractions. The number 1\(1)/(2) becomes (1×2+1)/2 which is 3/2, and the expression becomes 13.75×3/2 - 7×3/(4×2). The next step is to perform the multiplication in both terms. Simplifying, we have 13.75×3/2 = 20.625 and 7×3/4 = 5.25. Subtracting, we get 20.625 - 5.25 = 15.375.

To evaluate the expression, first simplify the mixed numbers which are provided in the expression, then multiply them by the accompanying numbers, and finally, subtract the second term from the first term. This step-by-step process helps us to solve the expression methodically and arrive at a final value. Double-checking the arithmetic ensures that the simplification is accurate and reasonable.

Therefore, the simplified expression is 12.

User Daverocks
by
8.2k points
5 votes

Final answer:

To simplify the expression, first simplify the inner parentheses, then substitute the values back and evaluate, we get 10.125.

Step-by-step explanation:

To simplify the expression 13.75(1(1)/(2))-7(1)/(4)(1(1)/(2)), we need to follow the order of operations (PEMDAS/BODMAS). First, we simplify the inner parentheses:

  1. (1(1)/(2)) = 1.5
  2. (1(1)/(2)) = 1.5

Then, we can substitute these values back into the expression and evaluate:

13.75(1.5) - 7(1.5) = 20.625 - 10.5 = 10.125

User Chen Leikehmacher
by
7.5k points