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Read this program and select the output. #include using namespace std; int main() { int a, b, sum ; double c ; a = 3; b = 5; c = 14.1; sum = a + b + c; c /= a; b += c - a; a *= 2 * b + c; cout << a << '\t' << b << '\t' << c << '\t' << sum << endl; return 0 ; }

User Hamelraj
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Final answer:

The program calculates the values of variables a, b, c, and sum. The line a *= 2 * b + c; multiplies the value of a by 2 * b + c. The output statement prints the current values of a, b, c, and sum separated by tabs.

Step-by-step explanation:

The given program calculates the values of variables a, b, c, and sum.

The line a *= 2 * b + c; multiplies the value of a by 2 * b + c. Then, the output statement, cout << a << ' ' << b << ' ' << c << ' ' << sum << endl;, prints the current values of a, b, c, and sum separated by tabs.

The output of the program will depend on the initial values of a, b, and c.

User Jon Derring
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