59.5k views
3 votes
Assuming that x is declared as variable of type double, which statement below is accurate regarding these two C++ statements? cout << int(x + 0.5);

cout << floor(x);

1 Answer

0 votes

Final answer:

The first statement rounds x to the nearest integer, while the second statement rounds it down to the nearest integer.

Step-by-step explanation:

The first statement, cout << int(x + 0.5);, rounds the value of x to the nearest integer by adding 0.5 and then converting it to an integer using the int() function. For example, if x is 3.2, the expression evaluates to 3.2 + 0.5 = 3.7, and the integer part is 3. So, it prints 3 to the console.

The second statement, cout << floor(x);, uses the floor() function to round down the value of x to the nearest integer. For example, if x is 3.2, the expression evaluates to 3.0, and it prints 3 to the console.

To summarize, the first statement rounds x to the nearest integer, while the second statement rounds it down to the nearest integer.

User Zujaj Misbah Khan
by
8.5k points