Question

Describe the steps involved in chemical synapse nervous impulse transmission.

A. Neurotransmitter binding to receptors initiates an action potential, which travels down the axon, leading to synaptic vesicle release and reuptake.
B. Action potential causes synaptic vesicle release, neurotransmitters bind to receptors, generating a postsynaptic potential, and reuptake terminates the signal.
C. Neurotransmitter binding to receptors triggers reuptake, which leads to action potential generation, synaptic vesicle release, and postsynaptic potential.
D. Synaptic vesicle release initiates an action potential, neurotransmitters bind to receptors, generating a postsynaptic potential, and reuptake terminates the signal.

Answer 1

The correct sequence for chemical synapse nervous impulse transmission involves an action potential causing the release of neurotransmitters, which bind to receptors and generate a postsynaptic potential, and ends with reuptake to terminate the signal.

Step-by-step explanation:

The correct sequence of steps involved in chemical synapse nervous impulse transmission is most accurately described by option B. Here is the step-by-step process:

1. An action potential travels down the axon to the axon terminal.
2. The arrival of the action potential causes synaptic vesicles to release neurotransmitters into the synaptic cleft.
3. The neurotransmitters travel across the synapse and bind to receptors on the postsynaptic neuron, generating a postsynaptic potential.
4. This postsynaptic potential can initiate a new action potential in the postsynaptic neuron if the threshold is reached.
5. Finally, to terminate the signal and prevent continuous activation, the neurotransmitters are removed from the synaptic cleft through reuptake, where they are often reabsorbed by the presynaptic neuron or broken down.