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19 votes
19 votes
29. The school that Lilly goes to is selling tickets to a drama performance. On the first day of ticket sales the

school sold 3 adult tickets and 1 child ticket for a total of $38. The school took in $104 on the second
day by selling 6 adult tickets and 4 child tickets. Find the price of an adult ticket and the price of a child
ticket.

User Cola
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1 Answer

25 votes
25 votes

Answer:

the price of an adult ticket is $8, and the price of a child ticket is $14.

Explanation:

To find the price of an adult ticket and the price of a child ticket, we need to set up a system of equations. Let "A" represent the price of an adult ticket and "C" represent the price of a child ticket.

On the first day, the school sold 3 adult tickets and 1 child ticket for a total of $38, so we can set up the following equation to represent this information:

3A + C = 38

On the second day, the school took in $104 by selling 6 adult tickets and 4 child tickets, so we can set up the following equation to represent this information:

6A + 4C = 104

Now that we have our two equations, we can solve for the values of A and C. We can use the elimination method to solve this system of equations. To do this, we need to multiply one of the equations by a constant so that one of the variables has the same coefficient in both equations. We'll multiply the first equation by 2:

6A + 2C = 76

We can then subtract this equation from the second equation to eliminate the C term:

6A + 4C - 6A - 2C = 104 - 76

This simplifies to:

0A + 2C = 28

Dividing both sides by 2, we get:

C = 14

We can now substitute this value for C in one of our original equations and solve for A. We'll use the first equation:

3A + 14 = 38

Subtracting 14 from both sides, we get:

3A = 24

Dividing both sides by 3, we get:

A = 8

Therefore, the price of an adult ticket is $8, and the price of a child ticket is $14.

User Starry
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