Final answer:
The probability of spinning a spinner twice and first landing on a factor of 70 and then on the number 5 is 12%.
Step-by-step explanation:
You are asking about the probability of spinning a spinner with numbers 1 to 5 and first landing on a factor of 70 and then on the number 5. To solve this, we need to consider each event separately and then multiply their probabilities together.
The factors of 70 are 1, 2, 5, 7, 10, 14, 35, and 70. On our spinner, the factors of 70 are 1, 2, and 5. Therefore, there are 3 favorable outcomes out of 5 possible outcomes for landing on a factor of 70. So, the probability of landing on a factor of 70 is 3/5 or 60%.
Next, for landing on the number 5, there is only one outcome which is the number 5 itself. Hence, the probability for this is 1/5 or 20%.
The probability of both events occurring in sequence is the product of their individual probabilities. Therefore, 60% (for a factor of 70) multiplied by 20% (for landing on 5) equals 12%. The overall probability of landing on a factor of 70 first and then landing on a 5 when spinning the spinner twice is 12%.