Question

What is the percent yield of PI₃, if 58.62 g of I₂ are reacted with an excess of phosphorus and 60.75 g of PI₃ are actually obtained?

Answer 1

The percent yield of PI₃ is 77.38%.

Step-by-step explanation:

The percent yield can be calculated using the formula:

Percent Yield = (Actual Yield / Theoretical Yield) x 100%

To calculate the percent yield of PI₃, we need to determine the theoretical yield first. The balanced equation for the reaction is:

3I₂ + 2P → 2PI₃

The molar mass of I₂ is 253.808 g/mol and the molar mass of PI₃ is 411.692 g/mol. Using the given mass of I₂ (58.62 g), we can calculate the theoretical yield:

(58.62 g I₂) x (1 mol I₂ / 253.808 g I₂) x (2 mol PI₃ / 3 mol I₂) x (411.692 g PI₃ / 1 mol PI₃) = 78.52 g PI₃

Now, we can calculate the percent yield:

Percent Yield = (Actual Yield / Theoretical Yield) x 100%

= (60.75 g / 78.52 g) x 100% = 77.38%