Final answer:
The spectator ions in the chemical reaction 2AlCl₃(aq) + 3Pb(NO₃)₂(aq) → 3PbCl₂(s) + 2Al(NO₃)₂(aq) are Al³⁺ and NO₃⁻.
Step-by-step explanation:
In the chemical equation 2AlCl₃(aq) + 3Pb(NO₃)₂(aq) → 3PbCl₂(s) + 2Al(NO₃)₂(aq), the spectator ions are ions that appear in identical forms on both the reactant and product sides of the equation, meaning they do not participate in the reaction itself. Upon examining the equation, one can determine that the spectator ions are the Al³⁺(Aluminum ions) and the NO₃⁻(Nitrate ions). Both of these ions are present as reactants and products in aqueous form and do not change throughout the course of the reaction. Therefore, the correct answer to the question would be c. Al³⁺; NO₃⁻.