Question

What is the effect of the following code

template
void printValues(T a, U b)

A) Prints the values of 'a' and 'b' with default precision
B) Prints the values of 'a' and 'b' with double precision
C) Prints the values of 'a' and 'b' with the specified template types
D) Results in a compilation error

Answer 1

The code template 'void printValues(T a, U b)' prints the values with the specified template types and precision is determined by the default or specified formatting, not by the template itself.

Step-by-step explanation:

The code template void printValues(T a, U b) will have the effect described in option C: Prints the values of 'a' and 'b' with the specified template types. Template functions in programming languages like C++ allow functions to operate with generic types. The actual type for T and U will be determined at compile time based on the arguments passed to the function. The precision of the printed values is not affected by the template types and will depend on how they are printed (e.g., using std::cout), and the default precision settings or any specified formatting commands.