Question

What is the equivalent pointer notation to the following

int *x = new int[5];
for (int i = 0; i++; i<5)
{
x[i] = i;
}:
A. int *x = {0, 1, 2, 3, 4}
B. int *x = new int[5] {0, 1, 2, 3, 4}
C. int *x = new int[5] {1, 2, 3, 4, 5}
D. int *x = {1, 2, 3, 4, 5}

Answer 1

The correct equivalent pointer notation is B. int *x = new int[5] {0, 1, 2, 3, 4}, which initializes the array with values corresponding to the indices, just as the loop in the snippet does.

Step-by-step explanation:

The correct equivalent pointer notation to the code int *x = new int[5]; for (int i = 0; i++; i<5) { x[i] = i; } is B. int *x = new int[5] {0, 1, 2, 3, 4}. This option directly initializes the dynamically allocated integer array with the values from 0 to 4. It's a more concise way to do the same thing as the loop in the given snippet, which populates the array with indices.The equivalent pointer notation to the given code is option A. int *x = {0, 1, 2, 3, 4}. In the given code, x is a pointer to an int. The new keyword is used to allocate memory for an array of 5 integers. The loop then assigns the values 0 to 4 to the elements of the array.