Question

Is this code valid

int main()
{
int array[3] = {1,2,3};
int *ptr = array;

int array2[3] = {3,5,7};
array2 = ptr;
}**

A) Yes
B) No
C) Only if 'array' and 'array2' have the same type
D) Only if 'ptr' is declared as an array

Answer 1

No, the code is not valid because you cannot directly assign one array to another in C. To copy array elements, use a loop or a memory copy function.

Step-by-step explanation:

The code provided in the question is not valid; specifically, the attempt to assign the pointer ptr to the array array2 is incorrect. In C, you cannot assign an array to another array directly. The correct way to copy contents from one array to another is to use a loop or a function like memcpy from the string.h library.

To declare a method as inline when it is defined outside the class declaration in C++, you should include the inline keyword before the function return type when you provide the definition of the method. Among the options provided, the correct syntax is A) inline void methodName();. When you define the function, you should also repeat the inline keyword before the function return type in the definition, outside the class.