Question

Solid ammonium chloride, NH, Cl, is formed by the reaction of gaseous ammonia, NH3, and hydrogen chloride, HCI. Macmillan Learning NH, (g) + HCl(g) → NH4Cl(s) A 4.18 g sample of NH, gas and a 4.18 g sample of HCl gas are mixed in a 0.50 L. flask at 25 °C. Identify the limiting reagent.

Answer 1

HCl is the limiting reagent because there are fewer moles of HCl than NH3, and the reaction stoichiometry is 1:1.

To find the limiting reagent in the reaction of NH3 with HCl, calculate the number of moles of each reactant.

Step-by-step explanation:

To determine the limiting reagent in the reaction of gaseous ammonia (NH₃) with hydrogen chloride (HCl) to form ammonium chloride (NH₄Cl), we must compare the mole ratio of the reactants to the stoichiometry of the balanced chemical equation. The balanced chemical equation for this reaction is:

NH₃(g) + HCl(g) → NH₄Cl(s)

First, we calculate the number of moles of each reactant:

• Moles of NH₃ = (4.18 g) / (17.03 g/mol)
• = 0.2455 mol
• Moles of HCl = (4.18 g) / (36.46 g/mol)
• = 0.1147 mol

The stoichiometry of the reaction is 1:1, meaning 1 mole of NH₃ reacts with 1 mole of HCl to produce 1 mole of NH₄Cl. Since we have more moles of NH₃ than HCl, HCl will be the limiting reagent.