33.4k views
2 votes
The scores on a test were normally distributed with a mean of 160 and a standard deviation of 9.44. A randomly selected student scored 176 on the test. What is the z-score that corresponds to the student's score of 176? Round to two decimal places.

1 Answer

5 votes

Final answer:

To calculate the z-score for a test score of 176 with a mean of 160 and a standard deviation of 9.44, subtract the mean from the score (176 - 160 = 16) and then divide by the standard deviation (16 / 9.44 ≈ 1.6958), which results in a z-score of approximately 1.70 when rounded.

Step-by-step explanation:

The student has a question about how to calculate a z-score for a given score from a normal distribution. In this case, the z-score corresponding to a test score of 176 can be calculated using the formula z = (x - µ) / σ, where x is the score, µ is the mean of the distribution, and σ is the standard deviation. We are given that the mean (µ) is 160 and the standard deviation (σ) is 9.44.

To calculate the z-score for the student's score of 176:

  • Subtract the mean from the score: 176 - 160 = 16.
  • Divide the result by the standard deviation: 16 / 9.44 ≈ 1.6958.
  • Round the result to two decimal places: z ≈ 1.70.

Therefore, the z-score that corresponds to the student's score of 176 is 1.70.

User Jortega
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories