Question

Identify the spectator ion(s) in the following reaction.

L(OH)2(s) + 2T (aq) + 2OH(aq) --> 2T*(aq) + L(OH)4 (aq)
T+
O and L(OH)4²-
0
O L(OH)2
O L(OH)₂²-
2-
T+ and OH
O
T+

Answer 1

In the given equation, all ions are involved in the reaction and none remain unchanged; hence, there are no spectator ions.

Step-by-step explanation:

In the given reaction, the spectator ions are the ions that do not participate in the actual chemical change and remain unchanged throughout the reaction. The spectator ions can be identified by comparing the ions present on both sides of the equation. In this case, the spectator ions are T+ and OH.

To identify the spectator ion(s) in the reaction provided, we must first understand what a spectator ion is. A spectator ion is an ion that does not participate in the chemical reaction and remains unchanged on both the reactant and product sides of the equation. In the equation L(OH)2(s) + 2T+ (aq) + 2OH- (aq) → 2T*(aq) + L(OH)42- (aq), there are no ions that remain unchanged; all ions are involved in forming new compounds. Therefore, there are no spectator ions in this reaction.