Answer:
Explanation:
y=ax^2+bx+c we are given point (0,5) so if x=0, y=c, so c=5. We have two other points
(2,3)(4,9) which gives us
4a+2b+5=3 and 16a+4b+5=9
Subtracting twice the first from the second
16a+4b+5-8a-4b-10=9-6
8a-5=3
8a=8, so a=1, so using 4a+2b+5=3 we get
4(1)+2b+5=3
2b+9=3
2b=-6
b=-3 so our quadratic is
y=x^2-3x+5