Question

What is the last number printed out when the following fragment executes?

int i = 4;
while (i>0) {
cout << i << endl;
i--;
}

A. 1
B. 3
C. 4
C. 5

Answer 1

The last number printed out by the given C++ code fragment is 1. The code uses a decrementing while loop that stops when the value of i is no longer greater than 0.

Step-by-step explanation:

The question pertains to the last number that will be printed by a fragment of code written in C++. When examining the code, it's clear that it is using a while loop that decrements the value of i with each iteration, starting from 4 and continuing as long as i is greater than 0. On each iteration, the code prints the current value of i and then decrements i.

The last number printed occurs when i equals 1 because after this value is printed, the decrement operation i-- is executed, resulting in i being 0. At this point, the condition i > 0 is no longer true, the loop terminates, and no further numbers are printed.

Therefore, the answer to "What is the last number printed out when the following fragment executes?" is A. 1.