Question

What is the output when the following code fragment executes?

int i=10;
for (int i = 0; i <= 5; i++)
cout << i+1 << '-';
cout << i;

Answer 1

Ignoring a redefinition error, the output would be '1-2-3-4-5-6-10', with each number from 1-6 followed by a dash, and ending with the value 10, due to separate scopes of variable 'i' in the loop and outside the loop.

Step-by-step explanation:

The code provided in the question contains a redefinition of variable 'i' which is not allowed in C++. Ignoring the redefinition error, assuming the code meant to either use a different variable name inside the loop or to not declare i before the loop, the output of this code fragment would be the sequence of numbers from 1 to 6 followed by a dash and then the number 10. This is because the for loop iterates with a different i (assuming it can be compiled), incrementing it from 0 up to 5, printing i+1 followed by a dash on each iteration. After the loop executes, the original i (outside the scope of the loop, with a value of 10) is printed.

However, as originally written with the redeclaration error, the code would not compile.