17.3k views
5 votes
The energy of an oscillator decreases to 36.8% of its initial value in 10.0 sec. What is the value of the time constant? (Pick the closest answer)

A. 1.0 sec
B. 2.0 sec
C. 3.0 sec
D. 4.0 sec
E. 5.0 sec

User DomincJune
by
7.1k points

1 Answer

2 votes

Final answer:

To find the time constant of a damped oscillator that decreases to 36.8% of its initial energy in 10.0 seconds, we use the decay formula and solve for the time constant, yielding a value just over 5 seconds. The closest provided answer is E. 5.0 sec.

Step-by-step explanation:

The student is asking about the time constant of a damped oscillator that decreases its energy to 36.8% of its initial value in 10.0 seconds. The time constant (τ) can be found using the property that the energy (E) of a damped oscillator decreases according to the equation E = E0e−t/τ, where E0 is the initial energy, t is the time, and τ is the time constant.

Solving for τ using the given information (E/E0 = 0.368 and t = 10.0s), we find that τ ≈ 10.0s / ln(1/0.368), resulting in a time constant just over 5 seconds. The closest answer provided is E. 5.0 sec.

User Ulab
by
7.3k points

No related questions found