Question

Two identical twins (same mass, height, etc) are standing on a dance floor. Twin A is wearing a pair of high heels and Twin B is barefoot. Which twin exerts more force on the floor?

A) Twin A
B) Twin B
C) Both exert the same force
D) Cannot be determined

Answer 1

Both twins exert the same force on the dance floor. The only difference is the pressure each one applies; Twin A in high heels applies greater pressure due to the smaller surface area, while Twin B exerts less pressure over a larger area.

Step-by-step explanation:

The question posed is regarding the force exerted by each twin on the dance floor. Since the mass and height of both twins are identical and the only difference is that Twin A is wearing high heels while Twin B is barefoot, we need to consider the area over which their weight is distributed. According to physics and the equation for pressure (P = F/A, where P is pressure, F is force, and A is area), the force exerted on the floor by each twin (which is equal to their weight) will be the same regardless of the area of contact with the floor. The difference is in the pressure exerted: Twin A will exert a higher pressure due to the smaller surface area of the high heels, whereas Twin B will have a lower pressure over a larger area. Therefore, the correct answer is C) Both exert the same force.