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Calculate the total power in a series parallel circuit, where the power source is 28V and R1, is 40 and in series with R2 and R3. R2 and R3 are in parallel and each is 50 ohms

1 Answer

1 vote

Answer:

12.06 W

Explanation:


\Sigma R=R_1+(1)/((1)/(R_2)+(1)/(R_3) )


=40+(1)/((1)/(50) +(1)/(50) )


=40+25


=65\ \Omega


\boxed{P=(V^2)/(R) }


P=(28^2)/(65)


=12.06\ W

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