Question

Two containers designed to hold water are side by side, both in the shape of a

cylinder. Container A has a radius of 13 feet and a height of 18 feet. Container B has a
radius of 11 feet and a height of 20 feet. Container A is full of water and the water is
pumped into Container B until Conainter B is completely full.
To the nearest tenth, what is the percent of Container A that is full after the pumping
is complete?
Container A

R= 13
h=18
Container B
2=11
h=20

Answer 1

To find the volume of water that was pumped from container A, we first need to find the volume of each container. We can use the formula for the volume of a cylinder to do this. The formula is V = πr^2h, where r is the radius of the cylinder and h is the height.

For container A, the volume is V = π * 13^2 * 18 = 8640π cubic feet

For container B, the volume is V = π * 11^2 * 20 = 7320π cubic feet

Since the water from container A completely filled container B, the volume of water that was pumped from container A is 8640π - 7320π = 1320π cubic feet.

To find the percent of container A that is full, we need to divide the volume of water remaining in container A by the total volume of container A and multiply by 100%. The total volume of container A is 8640π cubic feet, and after the water was pumped into container B, the volume of water remaining in container A is 8640π - 1320π = 7320π cubic feet.

Therefore, the percent of container A that is full is 7320π / 8640π * 100% = approximately 84.9% to the nearest tenth.