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For String c = ""hello world"";

The Java statements
int i = c.indexOf('o');
int j = c.lastIndexOf('l');
will result in:

a. i = 4 and j = 8.
b. i = 5 and j = 8.
c. i = 4 and j = 9.
d. i = 5 and j = 9."

1 Answer

7 votes

Final Answer;

For String c = "hello world", the result is i = 4 and j = 9, as the `indexOf('o')` method finds the first occurrence of 'o' at index 4, and `lastIndexOf('l')` locates the last 'l' at index 9 in the string "hello world." Thus, the correction option is C.

Step-by-step explanation:

In the given Java statements, the `indexOf('o')` method is used to find the index of the first occurrence of the character 'o' in the string "hello world." Since indexing starts from 0, the value of `i` would be 4 because 'o' first appears at the fifth position in the string.

Similarly, the `lastIndexOf('l')` method is used to find the index of the last occurrence of the character 'l' in the string. In the string "hello world," the last 'l' appears at the ninth position, so the value of `j` would be 9. Therefore, the result is **c. i = 4 and j = 9,** as the `indexOf` and `lastIndexOf` methods correctly locate the positions of 'o' and 'l' in the given string.

Understanding the behavior of these string manipulation methods is essential for effective programming in Java. The `indexOf` method returns the index of the first occurrence of a specified character, while `lastIndexOf` returns the index of the last occurrence. These operations are crucial for tasks such as searching and extracting information from strings. Thus, the correction option is C.

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