Answer:
the work done by friction on the car is 524,582 J.
Step-by-step explanation:
Given;
mass of the roller coaster, m = 800 kg
distance moved by the coaster, d = 225 ft = 68.58 m
final velocity of the coaster, v = 80 mi/h = 35.76 m/s
The time taken for the coaster to drop down the hill is calculated as;

The work done by friction on the car is calculated as;

Therefore, the work done by friction on the car is 524,582 J.