Question

Balance this equation

Al(OH)3+H2SO4=>Al3+ +SO42- +H2O a) Al(OH)3 + 3H2SO4 => Al2(SO4)3 + 3H2O
b) 2Al(OH)3 + 3H2SO4 => Al2(SO4)3 + 6H2O
c) Al(OH)3 + 2H2SO4 => Al2(SO4)3 + 2H2O
d) 2Al(OH)3 + H2SO4 => Al2(SO4)3 + 4H2O

Answer 1

The balanced equation is: 2Al(OH)₃ + 3H₂SO₄ => Al₂(SO₄)₃ + 3H₂O.

Step-by-step explanation:

The balanced equation for the reaction is a) 2Al(OH)₃ + 3H₂SO₄ => Al₂(SO₄)₃ + 3H₂O. In this equation, the reactants are aluminum hydroxide (Al(OH)3) and sulfuric acid (H2SO4), and the products are aluminum sulfate (Al₂(SO₄)3) and water (H₂O).

To balance the equation, we need to make sure that the number of each type of atom on both sides of the equation is equal. In this case, we have 1 aluminum on the left side and 2 on the right side, so we need to double the coefficient of Al(OH)₃. Similarly, we have 4 hydrogen on the left side and 6 on the right side, so we need to triple the coefficient of H₂O. All other atoms are already balanced.

The balanced equation is: 2Al(OH)₃ + 3H₂SO₄ => Al₂(SO₄)₃ + 3H₂O.