Question

Suppose you analyze a sample of fertilizer by the procedure of the experiment and obtain 1.000g of MgNH₄PO₄ x 6H₂O as the product. Calculate the equivalent mass of P₂O₅ initially in the sample?

a) 0.241 g
b) 0.345 g
c) 0.456 g
d) 0.543 g

Answer 1

The calculation of the mass of P2O5 from a sample of MgNH4PO4 x 6H2O requires information on stoichiometry and molar masses. Without specific experimental details, an accurate answer cannot be provided.

Step-by-step explanation:

The question involves a gravimetric analysis where a student needs to calculate the equivalent mass of P2O5 present in a fertilizer sample, given that a 1.000g sample of MgNH4PO4 x 6H2O is obtained from the experiment. This is a typical example of a problem that would be encountered in an analytical or general chemistry course.

As this type of calculation requires detailed chemical knowledge and the exact experimental conditions, such as stoichiometry, the molar mass of the compounds involved, and the balanced chemical equations, a complete answer cannot be provided without this specific information. It should typically involve converting the mass of MgNH4PO4 x 6H2O to moles, using its molar mass, and then using the stoichiometry of the reaction to find the equivalent moles (and thus mass) of P2O5.