Question

Al+KOH+H2O => K+ + Al(OH)4- + H2

a) Al + 3KOH + 3H2O => 3K+ + Al(OH)3 + 3H2
b) 2Al + 2KOH + 4H2O => 2K+ + 2Al(OH)3 + 3H2
c) 2Al + 6KOH + 3H2O => 2K+ + 2Al(OH)4- + 3H2
d) 3Al + 3KOH + 3H2O => 3K+ + Al(OH)3 + 3H2

Answer 1

The balanced reaction of aluminum with potassium hydroxide and water forms potassium ions, the aluminate ion, and hydrogen gas. The correct option from the given choices is c) 2Al + 6KOH + 3H2O => 2K+ + 2Al(OH)4- + 3H2.

Step-by-step explanation:

The correct balanced chemical reaction for aluminum reacting with potassium hydroxide (KOH) in the presence of water to form potassium ions (K+), a complex aluminate ion (Al(OH)4-), and hydrogen gas (H2) is:

2Al(s) + 2KOH(aq) + 6H2O(l) → 2K+(aq) + 2Al(OH)4−(aq) + 3H2(g)

This reaction involves aluminum being oxidized and hydroxide ions acting as a reducing agent.

Aluminum hydrolyzes in water to form aluminum hydroxide, which then reacts with excess hydroxide ions to form the aluminate ion. Hydrogen gas is produced as a byproduct.

The correct option from the given choices is c) 2Al + 6KOH + 3H2O => 2K+ + 2Al(OH)4- + 3H2