Final answer:
The complete ionic equation for the reaction between lead perchlorate and sodium sulfide shows all ions present and the formation of solid lead sulfide (PbS), while the net ionic equation shows only the ions involved in forming the precipitate.
Step-by-step explanation:
To write the complete ionic equation for the reaction between lead perchlorate and sodium sulfide, we need to consider the ions that each compound dissociates into in aqueous solution. Lead perchlorate breaks down into lead (II) ions (Pb2+) and perchlorate ions (ClO4-), while sodium sulfide breaks down into sodium ions (Na+) and sulfide ions (S2-). When these compounds react, the insoluble product lead sulfide (PbS) is formed, which precipitates out of the solution. The complete ionic equation shows all the ions that are present in the reaction, highlighting this precipitate formation.
Complete ionic equation:
Pb(NO3)2(aq) + 2Na+(aq) + S2-(aq) → PbS(s) + 2Na+(aq) + 2ClO4-(aq)
We can simplify this equation by canceling out the spectator ions, those that do not change during the reaction, to get the net ionic equation:
Net ionic equation:
Pb2+(aq) + S2-(aq) → PbS(s)