Question

A 45.2-mL sample of gas in a cylinder is warmed from 23 ∘C to 91 ∘C .

Answer 1

The new volume of the gas, given that the sample of the gas in the cylinder is warmed from 23 °C to 91 °C, is 55.6 mL

How to calculate the new volume of the gas?

According to the question given above, we were informed of the following:

• Initial volume of the gas sample (V₁) = 45.2 mL
• Initial temperature of the gas sample (T₁) = 23 °C = 23 + 273 = 296 K
• New temperature of the gas sample (T₂) = 91 °C = 91 + 273 = 364 K
• New volume of the gas sample (V₂) = ?

Now, we shall calculate the new volume of the gas sample by applying the Charle's law equation as shown below:

`(V_1)/(T_1) = (V_2)/(T_2) \\\\(45.2)/(296) = (V_2)/(364) \\\\Cross\ multiply\\\\296\ *\ V_2 = 45.2\ *\ 364\\\\V_2 = (45.2\ *\ 364)/(296)\\ \\V_2 = 55.6\ mL`

Thus, the new volume is 55.6 mL

Complete question:

A 45.2-mL sample of gas in a cylinder is warmed from 23 ∘C to 91 ∘C . What is the new volume of the gas