Final answer:
The Warren G. Harding memorial bathtub, which is four feet wide, six feet long, and three feet high, has a volume of 72 cubic feet. Converting this to gallons using the conversion of 7.48 gallons per cubic foot, it would take 538.56 gallons of water to fill the bathtub to the rim.
Step-by-step explanation:
To calculate the number of gallons of water needed to fill Warren G. Harding memorial bathtub to the rim, we first need to determine the volume of the bathtub in cubic feet and then convert that volume to gallons. The bathtub is four feet wide, six feet long, and three feet high. The formula for the volume of a rectangular prism (which is the shape of the bathtub) is length × width × height.
Volume in cubic feet = 6 feet (length) × 4 feet (width) × 3 feet (height) = 72 cubic feet.
To convert cubic feet to gallons, we use the fact that one cubic foot of water is equivalent to 7.48 gallons. Therefore, we multiply the volume in cubic feet by 7.48 to find the volume in gallons.
Volume in gallons = 72 cubic feet × 7.48 gallons/cubic foot = 538.56 gallons.
Therefore, 538.56 gallons of water are needed to fill the Warren G. Harding memorial bathtub to the rim.