Final answer:
Option (C), The prime factorization of a perfect cube (other than 0 or 1) will only have exponents that are multiples of 3.
Step-by-step explanation:
The prime factorization of a perfect cube (other than 0 or 1) will only have exponents that are multiples of 3.
To understand why, let's take an example. Suppose we have a perfect cube like 27. The prime factorization of 27 is 3 3. Here, the exponent 3 is a multiple of 3, and it represents the number of times the prime factor 3 is multiplied by itself.
Similarly, if we have a perfect cube like 64, the prime factorization of 64 is 2 6. Here, the exponent 6 is also a multiple of 3, representing that the prime factor 2 is multiplied by itself six times.
Therefore, the correct answer is C) multiples of 3.