Pressure is force per unit area. The man (80 kg) exerts 1.30 pressure on flat-soled shoes (2 × 300 cm²), while a woman, same weight, applies 5.6 pressure with high-heeled shoes (2 × 70 cm²).
Pressure is defined as the force applied per unit area. In this scenario, the pressure applied by the man can be calculated by dividing his weight by the total area of the soles of his shoes. The man weighs 80 kg, and assuming he distributes his weight evenly, the force exerted by him on the floor is the gravitational force, which is the product of his mass and the acceleration due to gravity (approximately 9.8 m/s²).
The pressure exerted by the man is given by the formula:
Pressure (man) = Force (man) / Area (man), where Pressure (man) = Weight of man / Area of man's shoes.
Substituting the values:
Pressure (man) = (80 kg) × (9.8 m/s²) / (2 × 300 cm²).
= 1.30
The pressure exerted by the man would be 1.30
For the woman, the pressure can be similarly calculated using the weight of the woman and the area of her high-heeled shoes.
The pressure exerted by the woman is given by the formula:
Pressure (woman) = Force (woman) / Area (woman),
Where :
Pressure (woman) = Weight of woman / Area of woman's shoes.
Substituting the values:
Pressure (woman) = (80 kg) × (9.8 m/s²) / (2 × 70 cm²).
= 5.6
The applied pressure would be 5.6.
The question probable may be:
2. A man weighing 80 kg and wearing a flat-soled pair of shoes of area 300 cm square each is standing on a
horizontal floor. What is the pressure applied by him on the floor? What would be the pressure applied
by a women of the same weight wearing a high heeled pair of shoes of area 70 cm² each?