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Use the alligation alternate to solve. How many mL of pure alcohol (100% alcohol ) must be added to 100mL of 60% alcohol to make 80% alcohol?

User Kias
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1 Answer

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Final answer:

To make an 80% alcohol solution, you need to add 50 mL of pure alcohol to 100 mL of 60% alcohol.

Step-by-step explanation:

The alligation alternate method can be used to solve this problem. To determine how many mL of pure alcohol is needed to make an 80% alcohol solution, we can set up the following diagram:

60% Alcohol Solution Pure Alcohol (100% Alcohol)

40 x 100

----------------- = -----------------

100 80

Cross multiplying and solving for x, we find that x = 50 mL. Therefore, 50 mL of pure alcohol must be added to the 100 mL of 60% alcohol to make an 80% alcohol solution.

User Treasha
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