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Write an equation of the line that passes through 6,5 and is perpendicular to the line y=-3x+3

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Final answer:

To find the equation of a line that is perpendicular to another line, use the negative reciprocal of the slope of the given line and the point-slope form of a linear equation. Final equation: y = (1/3)x + 3

Step-by-step explanation:

To find the equation of a line that is perpendicular to another line, we need to find the negative reciprocal of the slope of the given line. The given line has a slope of -3, so the perpendicular line will have a slope of 1/3. Let's use the point-slope form of a linear equation to find the equation of the perpendicular line.

Given point: (6, 5)

Slope of the perpendicular line: 1/3

Equation of the line: y - y1 = m(x - x1)

Substituting the values, we get: y - 5 = (1/3)(x - 6)

Simplifying, we get: y - 5 = (1/3)x - 2

Final equation: y = (1/3)x + 3

User Lutti Coelho
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