Question

How many molecues of NaCO₃ are contained in a 34.1 g sample?

Answer 1

To find the number of moles of NaCO₃ in a 34.1 g sample, divide the mass of the sample by its molar mass. There are approximately 0.401 moles of NaCO₃ in a 34.1 g sample.

Step-by-step explanation:

To find the number of moles of NaCO₃ in a 34.1 g sample, we need to divide the mass of the sample by its molar mass. The molar mass of NaCO₃ is 22.99 g/mol for Na, 12.01 g/mol for C, and 16.00 g/mol for O, so the molar mass of NaCO₃ is 85.00 g/mol.

We can calculate the number of moles using the equation:

moles = mass / molar mass

Thus, the number of moles of NaCO₃ in a 34.1 g sample is:

moles = 34.1 g / 85.00 g/mol

Calculating this value gives us:

moles = 0.401 moles

Therefore, there are approximately 0.401 moles of NaCO₃ in a 34.1 g sample.