Question

C_(7)H_(6)O_(3)(s)+C_(2)H_(4)O_(2)(I)->C_(9)H_(8)O_(4)(s)+H_(2)O(I) salicylic acid acetic acid aspirin How many grams of water are formed from 91. 3g of salicylic acid?

Answer 1

From the balanced equation, 1 mole of salicylic acid reacts with 1 mole of acetic acid to form 1 mole of aspirin and 1 mole of water. Therefore, 91.3 g of salicylic acid will form 18 g of water.

Step-by-step explanation:

In the given reaction, 1 mole of salicylic acid (C7H6O3) reacts with 1 mole of acetic acid (C2H4O2) to form 1 mole of aspirin (C9H8O4) and 1 mole of water (H2O).

From the balanced equation, we can see that the mole ratio of salicylic acid to water is 1:1. Therefore, if 1 mole of salicylic acid forms 1 mole of water, then 91.3 g of salicylic acid will form 18 g of water (since the molar mass of water is 18 g/mol).

Therefore, 91.3 g of salicylic acid will form 18 g of water.