Final answer:
408 grams of lead would displace approximately 35.98 milliliters (mL) of water, calculated using the density of lead (11.34 g/mL) and the mass of lead provided.
Step-by-step explanation:
The student's question relates to the displacement of water by a certain mass of lead. To answer this question, we use the concept of density. Density is the mass of an object divided by its volume. The density of lead is approximately 11.34 g/mL, which means that each milliliter of lead has a mass of 11.34 grams.
To find out how many milliliters of water would be displaced by 408 grams of lead, we perform the following calculation:
- Determine the volume of lead by dividing the mass by the density: Volume = Mass / Density.
- For 408 grams of lead: Volume = 408 grams / 11.34 g/mL.
- The result is approximately 35.98 mL, which is the volume of water that would be displaced by 408 grams of lead.
Therefore, 408 grams of lead would displace approximately 35.98 mL of water.