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In pea plants, the P allele encodes the purple flower color phenotype and is dominant over the p allele that encodes white flower color. What would be the phenotypic ratio of offspring form a Pp x PP cross?

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Final answer:

The phenotypic ratio of offspring from a cross between a heterozygous purple-flowered pea plant (Pp) and a homozygous dominant purple-flowered pea plant (PP) is 100% purple-flowered peas, as the P allele for purple flowers is dominant.

Step-by-step explanation:

In pea plants, the P allele encodes the purple flower color phenotype and is dominant over the p allele that encodes white flower color. When considering a cross between a heterozygous purple-flowered pea plant (Pp) and a homozygous dominant purple-flowered pea plant (PP), the phenotypic ratio of the offspring can be determined through a Punnett square analysis. For this particular cross, the potential genotypes of the offspring would be PP and Pp. Since both of these genotypes result in a purple flower due to the presence of the dominant P allele, all the offspring will display the purple flower phenotype. Therefore, the phenotypic ratio of the offspring from a Pp x PP cross will be 100% purple-flowered peas.

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