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Hemophilia B.... man without this disease has children with a woman who is heterozygous for this allele, what percentage of their off spring would be expected to have the disease?

User Youssef CH
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1 Answer

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Final answer:

In the case of hemophilia B, a man without the disease having children with a woman who is heterozygous for the allele results in a 50% chance of their offspring having hemophilia B.

Step-by-step explanation:

In the case of hemophilia B, it is an X-linked recessive disorder. A man without the disease has children with a woman who is heterozygous for the allele. Since the woman is heterozygous, she carries one normal allele and one mutated allele for hemophilia B.

Their offspring will have a 50% chance of inheriting the mutated allele from the mother and developing hemophilia B. The other 50% chance is that they inherit the normal allele from the mother and do not develop the disease. Therefore, 50% of their offspring would be expected to have hemophilia B.

User Martel
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