Final answer:
In the case of hemophilia B, a man without the disease having children with a woman who is heterozygous for the allele results in a 50% chance of their offspring having hemophilia B.
Step-by-step explanation:
In the case of hemophilia B, it is an X-linked recessive disorder. A man without the disease has children with a woman who is heterozygous for the allele. Since the woman is heterozygous, she carries one normal allele and one mutated allele for hemophilia B.
Their offspring will have a 50% chance of inheriting the mutated allele from the mother and developing hemophilia B. The other 50% chance is that they inherit the normal allele from the mother and do not develop the disease. Therefore, 50% of their offspring would be expected to have hemophilia B.