Final answer:
To determine the number of moles of AlNO₃ in 264g of the compound, divide the mass by the molar mass of AlNO₃. The molar mass of AlNO₃ is calculated by adding up the atomic masses of each element. In this case, the number of moles is approximately 4.13 moles.
Step-by-step explanation:
To determine the number of moles of AlNO₃ in 264g of the compound, we need to use the molar mass of AlNO₃. We can find the molar mass by adding up the atomic masses of each element in the compound.
The molar mass of AlNO₃ is calculated as follows:
- Molar mass of Al: 26.98 g/mol
- Molar mass of N: 14.01 g/mol
- Molar mass of O: 16.00 g/mol
Summing these values, we find that the molar mass of AlNO₃ is 63.99 g/mol.
To calculate the number of moles in 264g of AlNO₃, we can use the formula:
moles = mass / molar mass
Substituting the values, we get:
moles = 264g / 63.99 g/mol
≈ 4.13 moles