Final answer:
The gradient of a graph of ln K against 1/T represents the slope of the line, which is equal to the activation energy divided by the gas constant. This relationship is shown in the equation lnK = (-Ea/R)(1/T) + lnA.
Step-by-step explanation:
The gradient of a graph of ln K against 1/T represents the slope of the line. In this case, the slope of the line is equal to the activation energy divided by the gas constant, -Ea/R. This relationship is shown in the equation lnK = (-Ea/R)(1/T) + lnA, where Ea is the activation energy, R is the gas constant, and A is a constant.