Question

*In dogs, a dominant allele (W) produces wire-haired fur. The recessive allele (w) produces smooth fur. A homozygous wire-haired male is mated to a female with smooth hair. Create a Punnett square to show the possibilities that would result if these two dogs had puppies together.

a) List the possible genotypes and phenotypes for the puppies.

b) What is the probability that the puppies would have wire-hair?

c) What is the probability that the puppies would have smooth hair?

Answer 1

a) The possible genotypes for the puppies are WW and Ww, and the corresponding phenotypes are wire-haired and wire-haired/smooth-haired (carrier).

b) The probability that the puppies would have wire-hair is 100%.

c) The probability that the puppies would have smooth hair is 0%.

Step-by-step explanation:

a) The Punnett square for the cross between a homozygous wire-haired male (WW) and a female with smooth hair (ww) shows the possible genotypes (WW and Ww) and their corresponding phenotypes (wire-haired and wire-haired/smooth-haired).

b) All the puppies will inherit at least one dominant allele (W), resulting in wire-haired fur.

c) Since the female is homozygous for the recessive allele (ww), there is no possibility of smooth-haired puppies in this cross.