Final answer:
To solve the quadratic equation 4y²-8y-10=-5 using the quadratic formula, rearrange the equation to ax² + bx + c = 0. Substituting the values into the quadratic formula, simplify the equation and determine the solutions. In this case, the equation has no real solutions.
Step-by-step explanation:
To solve the quadratic equation 4y²-8y-10=-5 using the quadratic formula, we first need to rearrange the equation to get it in the form ax² + bx + c = 0. In this case, a=4, b=-8, and c=-5-(-10)=5. Substituting these values into the quadratic formula, we have:
y = (-b±√(b²-4ac))/(2a)
y = (-(-8)±√((-8)²-4(4)(5)))/(2(4))
Simplifying further, we get:
y = (8±√(64-80))/8
y = (8±√(-16))/8
Since we have a negative value under the square root, the equation has no real solutions. Therefore, the quadratic equation 4y²-8y-10=-5 has no solution.