Question

What reagant would you use for bacl2

Answer 1

The reagent you would use for BaCl2 is usually H2SO4, which stands for sulfuric acid.

Step-by-step explanation:

The reagent you would use for BaCl2 is usually H2SO4, which stands for sulfuric acid.

The reaction between BaCl2 and H2SO4 produces BaSO4 (barium sulfate) and HCl (hydrochloric acid).

This can be represented by the chemical equation:

BaCl2 + H2SO4 → BaSO4 + 2HCl

Answer 2

The reagent that would be used for BaCl2 is H2SO4 (sulfuric acid), which reacts with BaCl2 to form BaSO4 and HCl.

Step-by-step explanation:

The reagent that would be used for BaCl2 is H2SO4 (sulfuric acid). When BaCl2 reacts with H2SO4, it forms BaSO4 (barium sulfate) and HCl (hydrochloric acid) as products. The balanced equation for this reaction is:

BaCl2 + H2SO4 → BaSO4 + 2 HCl

So, if you have 2 grams of BaCl2, you would need to use the appropriate mass of H2SO4 to completely react with the BaCl2. The mass of H2SO4 can be determined using stoichiometry and the molar mass of BaCl2 and H2SO4.