Final answer:
To calculate the volume of KOH needed to neutralize H2SO4, determine the moles of H2SO4 from its mass, use the balanced chemical equation to find the mole ratio between H2SO4 and KOH, and finally calculate the volume using the KOH concentration.
Step-by-step explanation:
To find the volume of KOH solution used in the neutralization of H2SO4, we need to perform stoichiometric calculations. First, we start by determining the moles of H2SO4 in the given mass (36.2 g). Using the molar mass of H2SO4, we calculate the moles of H2SO4. Then, write the balanced chemical equation: H2SO4 + 2 KOH → K2SO4 + 2 H2O.
From the equation, we can see that 1 mole of H2SO4 requires 2 moles of KOH to neutralize. So we double the moles of H2SO4 to get the moles of KOH needed. Finally, divide the moles of KOH by the concentration of the KOH solution to find the volume of KOH in liters.
For instance, if 36.2 g of H2SO4 were neutralized by a 5.49 M KOH solution, the volume of KOH would be approximately 134 mL, calculated by dividing the moles of KOH needed by the concentration of the KOH solution.