184k views
0 votes
Calculate the wronskian of y1=8x and y2=3x

User Samanda
by
7.8k points

1 Answer

1 vote

Final answer:

The Wronskian of the functions y1 = 8x and y2 = 3x is calculated by evaluating the determinant of a matrix formed by these functions and their derivatives, resulting in a Wronskian value of 0.

Step-by-step explanation:

To calculate the Wronskian of two functions, y1 = 8x and y2 = 3x, we need to evaluate the determinant of a 2x2 matrix composed of these functions and their derivatives with respect to x. The Wronskian is defined as:

W(y1,y2) =
| y1 y2 |
| y1' y2' |

First, we need to find the derivatives of y1 and y2:

  • y1' = d(8x)/dx = 8
  • y2' = d(3x)/dx = 3

Now, we can construct the matrix and calculate its determinant:

W(y1,y2) =
| 8x 3x |
| 8 3 | = 8x*3 - 3x*8 = 0

Therefore, the Wronskian of y1 and y2 is 0.

User Gabriel Durac
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.