Question

Solve each system of equations
x=2y-1
3x-2y=-3

Answer 1

x = - 1 , y = 0

Explanation:

given the system of equations

x = 2y - 1 → (1)

3x - 2y = - 3 → (2)

substitute x = 2y - 1 into (2)

3(2y - 1) - 2y = - 3 ← distribute parenthesis and simplify left side

6y - 3 - 2y = - 3

4y - 3 = - 3 ( add 3 to both sides )

4y = 0 , then

y = 0

substitute y = 0 into (1) and solve for x

x = 2(0) - 1 = 0 - 1 = - 1

solution is x = - 1 , y = 0