Question

To find the distance between a point X and an inaccessible point Z, a line segment XY is constructed. Measurements show that XY = 934 m, angle XYZ = 39°48', and angle YZX = 115°18'. Find the distance between X and Z to the nearest meter.

39°48'
934 m
115°18
The distance between X and Z is m.
(Do not round until the final answer. Then round to the nearest meter as needed.)

Answer 1

The distance between X and Z is approximately 2159 meters.

Step-by-step explanation:

To find the distance between point X and point Z, we can use the Law of Sines.

Let's call the distance between X and Z as XZ.

Using the Law of Sines, we have:

XZ / sin(115°18')

= 934 / sin(39°48')

Now, we can solve for XZ:

XZ = (sin(115°18') / sin(39°48')) * 934

XZ ≈ 2159 m